ax(bxc)=(axb)xc

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Solution for ax(bxc)=(axb)xc equation: 


Simplifying
ax(bxc) = (axb) * xc

Multiply ax * bcx
abcx2 = (axb) * xc

Multiply abx * cx
abcx2 = abcx2

Add '-1abcx2' to each side of the equation.
abcx2 + -1abcx2 = abcx2 + -1abcx2

Combine like terms: abcx2 + -1abcx2 = 0
0 = abcx2 + -1abcx2

Combine like terms: abcx2 + -1abcx2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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