b(11b+1)=10

Solution for b(11b+1)=10 equation:

Simplifying
b(11b + 1) = 10

Reorder the terms:
b(1 + 11b) = 10
(1 * b + 11b * b) = 10
(1b + 11b2) = 10

Solving
1b + 11b2 = 10

Solving for variable 'b'.

Reorder the terms:
-10 + 1b + 11b2 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + 1b + 11b2 = 0

Factor a trinomial.
(-1 + -1b)(10 + -11b) = 0

Subproblem 1
Set the factor '(-1 + -1b)' equal to zero and attempt to solve:

Simplifying
-1 + -1b = 0

Solving
-1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1b = 0 + 1
-1b = 0 + 1

Combine like terms: 0 + 1 = 1
-1b = 1

Divide each side by '-1'.
b = -1

Simplifying
b = -1
Subproblem 2
Set the factor '(10 + -11b)' equal to zero and attempt to solve:

Simplifying
10 + -11b = 0

Solving
10 + -11b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -11b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -11b = 0 + -10
-11b = 0 + -10

Combine like terms: 0 + -10 = -10
-11b = -10

Divide each side by '-11'.
b = 0.9090909091

Simplifying
b = 0.9090909091
Solution
b = {-1, 0.9090909091}