b(1b+5)+3(b+5)=

Solution for b(1b+5)+3(b+5)= equation:

Simplifying
b(1b + 5) + 3(b + 5) = 0

Reorder the terms:
b(5 + 1b) + 3(b + 5) = 0
(5 * b + 1b * b) + 3(b + 5) = 0
(5b + 1b2) + 3(b + 5) = 0

Reorder the terms:
5b + 1b2 + 3(5 + b) = 0
5b + 1b2 + (5 * 3 + b * 3) = 0
5b + 1b2 + (15 + 3b) = 0

Reorder the terms:
15 + 5b + 3b + 1b2 = 0

Combine like terms: 5b + 3b = 8b
15 + 8b + 1b2 = 0

Solving
15 + 8b + 1b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + b)(3 + b) = 0

Subproblem 1
Set the factor '(5 + b)' equal to zero and attempt to solve:

Simplifying
5 + b = 0

Solving
5 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + b = 0 + -5
b = 0 + -5

Combine like terms: 0 + -5 = -5
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(3 + b)' equal to zero and attempt to solve:

Simplifying
3 + b = 0

Solving
3 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + b = 0 + -3
b = 0 + -3

Combine like terms: 0 + -3 = -3
b = -3

Simplifying
b = -3
Solution
b = {-5, -3}