b(2)+b(2)*10(2)=168

Solution for b(2)+b(2)*10(2)=168 equation:

b(2)+b(2)*10(2)=168

We move all terms to the left:

b(2)+b(2)*10(2)-(168)=0

We add all the numbers together, and all the variables

b^2+b2*102-168=0

Wy multiply elements

b^2+102b^2-168=0

We add all the numbers together, and all the variables

103b^2-168=0

a = 103; b = 0; c = -168;
Δ = b2-4ac
Δ = 02-4·103·(-168)
Δ = 69216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{69216}=\sqrt{16*4326}=\sqrt{16}*\sqrt{4326}=4\sqrt{4326}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{4326}}{2*103}=\frac{0-4\sqrt{4326}}{206}
=-\frac{4\sqrt{4326}}{206}
=-\frac{2\sqrt{4326}}{103}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{4326}}{2*103}=\frac{0+4\sqrt{4326}}{206}
=\frac{4\sqrt{4326}}{206}
=\frac{2\sqrt{4326}}{103}
$