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b(2+b)=-12
We move all terms to the left:
b(2+b)-(-12)=0
We add all the numbers together, and all the variables
b(b+2)-(-12)=0
We add all the numbers together, and all the variables
b(b+2)+12=0
We multiply parentheses
b^2+2b+12=0
a = 1; b = 2; c = +12;
Δ = b2-4ac
Δ = 22-4·1·12
Δ = -44
Delta is less than zero, so there is no solution for the equation
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