b(20b-3)-2=0

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Solution for b(20b-3)-2=0 equation:


Simplifying
b(20b + -3) + -2 = 0

Reorder the terms:
b(-3 + 20b) + -2 = 0
(-3 * b + 20b * b) + -2 = 0
(-3b + 20b2) + -2 = 0

Reorder the terms:
-2 + -3b + 20b2 = 0

Solving
-2 + -3b + 20b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-1 + -4b)(2 + -5b) = 0

Subproblem 1

Set the factor '(-1 + -4b)' equal to zero and attempt to solve: Simplifying -1 + -4b = 0 Solving -1 + -4b = 0 Move all terms containing b to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4b = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4b = 0 + 1 -4b = 0 + 1 Combine like terms: 0 + 1 = 1 -4b = 1 Divide each side by '-4'. b = -0.25 Simplifying b = -0.25

Subproblem 2

Set the factor '(2 + -5b)' equal to zero and attempt to solve: Simplifying 2 + -5b = 0 Solving 2 + -5b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5b = 0 + -2 -5b = 0 + -2 Combine like terms: 0 + -2 = -2 -5b = -2 Divide each side by '-5'. b = 0.4 Simplifying b = 0.4

Solution

b = {-0.25, 0.4}

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