b(3/4b-156)=0

Solution for b(3/4b-156)=0 equation:

b(3/4b-156)=0


Domain of the equation: 4b-156)!=0

b∈R


We multiply parentheses

3b^2-156b=0

a = 3; b = -156; c = 0;
Δ = b2-4ac
Δ = -1562-4·3·0
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-156)-156}{2*3}=\frac{0}{6}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-156)+156}{2*3}=\frac{312}{6}
=52
$