b(5b-4)-12=0

Solution for b(5b-4)-12=0 equation:

Simplifying
b(5b + -4) + -12 = 0

Reorder the terms:
b(-4 + 5b) + -12 = 0
(-4 * b + 5b * b) + -12 = 0
(-4b + 5b2) + -12 = 0

Reorder the terms:
-12 + -4b + 5b2 = 0

Solving
-12 + -4b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-6 + -5b)(2 + -1b) = 0

Subproblem 1
Set the factor '(-6 + -5b)' equal to zero and attempt to solve:

Simplifying
-6 + -5b = 0

Solving
-6 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -5b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -5b = 0 + 6
-5b = 0 + 6

Combine like terms: 0 + 6 = 6
-5b = 6

Divide each side by '-5'.
b = -1.2

Simplifying
b = -1.2
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {-1.2, 2}