b(5px-c)=a(qx-4)

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Solution for b(5px-c)=a(qx-4) equation:


Simplifying
b(5px + -1c) = a(qx + -4)

Reorder the terms:
b(-1c + 5px) = a(qx + -4)
(-1c * b + 5px * b) = a(qx + -4)
(-1bc + 5bpx) = a(qx + -4)

Reorder the terms:
-1bc + 5bpx = a(-4 + qx)
-1bc + 5bpx = (-4 * a + qx * a)
-1bc + 5bpx = (-4a + aqx)

Solving
-1bc + 5bpx = -4a + aqx

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Reorder the terms:
4a + -1aqx + -1bc + 5bpx = -4a + aqx + 4a + -1aqx

Reorder the terms:
4a + -1aqx + -1bc + 5bpx = -4a + 4a + aqx + -1aqx

Combine like terms: -4a + 4a = 0
4a + -1aqx + -1bc + 5bpx = 0 + aqx + -1aqx
4a + -1aqx + -1bc + 5bpx = aqx + -1aqx

Combine like terms: aqx + -1aqx = 0
4a + -1aqx + -1bc + 5bpx = 0

The solution to this equation could not be determined.

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