b(9-2)=6(2-b)=

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Solution for b(9-2)=6(2-b)= equation: 



b(9-2)=6(2-b)=

We move all terms to the left:

b(9-2)-(6(2-b))=0

We add all the numbers together, and all the variables

b7-(6(-1b+2))=0

We add all the numbers together, and all the variables

b^7-(6(-1b+2))=0



We calculate terms in parentheses: -(6(-1b+2)), so:

6(-1b+2)

We multiply parentheses

-6b+12

Back to the equation:

-(-6b+12)



We do not support ebpression: b^7

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