b(9-2b)=26

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Solution for b(9-2b)=26 equation: 



b(9-2b)=26

We move all terms to the left:

b(9-2b)-(26)=0

We add all the numbers together, and all the variables

b(-2b+9)-26=0

We multiply parentheses

-2b^2+9b-26=0

a = -2; b = 9; c = -26;
Δ = b2-4ac
Δ = 92-4·(-2)·(-26)
Δ = -127
Delta is less than zero, so there is no solution for the equation

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