b(b+2)=24

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Solution for b(b+2)=24 equation:


Simplifying
b(b + 2) = 24

Reorder the terms:
b(2 + b) = 24
(2 * b + b * b) = 24
(2b + b2) = 24

Solving
2b + b2 = 24

Solving for variable 'b'.

Reorder the terms:
-24 + 2b + b2 = 24 + -24

Combine like terms: 24 + -24 = 0
-24 + 2b + b2 = 0

Factor a trinomial.
(-6 + -1b)(4 + -1b) = 0

Subproblem 1

Set the factor '(-6 + -1b)' equal to zero and attempt to solve: Simplifying -6 + -1b = 0 Solving -6 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1b = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1b = 0 + 6 -1b = 0 + 6 Combine like terms: 0 + 6 = 6 -1b = 6 Divide each side by '-1'. b = -6 Simplifying b = -6

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {-6, 4}

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