b(b+8)=128

Solution for b(b+8)=128 equation:

Simplifying
b(b + 8) = 128

Reorder the terms:
b(8 + b) = 128
(8 * b + b * b) = 128
(8b + b2) = 128

Solving
8b + b2 = 128

Solving for variable 'b'.

Reorder the terms:
-128 + 8b + b2 = 128 + -128

Combine like terms: 128 + -128 = 0
-128 + 8b + b2 = 0

Factor a trinomial.
(-16 + -1b)(8 + -1b) = 0

Subproblem 1
Set the factor '(-16 + -1b)' equal to zero and attempt to solve:

Simplifying
-16 + -1b = 0

Solving
-16 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + -1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + -1b = 0 + 16
-1b = 0 + 16

Combine like terms: 0 + 16 = 16
-1b = 16

Divide each side by '-1'.
b = -16

Simplifying
b = -16
Subproblem 2
Set the factor '(8 + -1b)' equal to zero and attempt to solve:

Simplifying
8 + -1b = 0

Solving
8 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + -1b = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -1b = 0 + -8
-1b = 0 + -8

Combine like terms: 0 + -8 = -8
-1b = -8

Divide each side by '-1'.
b = 8

Simplifying
b = 8
Solution
b = {-16, 8}