b(b-3)=-40

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Solution for b(b-3)=-40 equation: 


Simplifying
b(b + -3) = -40

Reorder the terms:
b(-3 + b) = -40
(-3 * b + b * b) = -40
(-3b + b2) = -40

Solving
-3b + b2 = -40

Solving for variable 'b'.

Reorder the terms:
40 + -3b + b2 = -40 + 40

Combine like terms: -40 + 40 = 0
40 + -3b + b2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-40' to each side of the equation.
40 + -3b + -40 + b2 = 0 + -40

Reorder the terms:
40 + -40 + -3b + b2 = 0 + -40

Combine like terms: 40 + -40 = 0
0 + -3b + b2 = 0 + -40
-3b + b2 = 0 + -40

Combine like terms: 0 + -40 = -40
-3b + b2 = -40

The b term is -3b.  Take half its coefficient (-1.5).
Square it (2.25) and add it to both sides.

Add '2.25' to each side of the equation.
-3b + 2.25 + b2 = -40 + 2.25

Reorder the terms:
2.25 + -3b + b2 = -40 + 2.25

Combine like terms: -40 + 2.25 = -37.75
2.25 + -3b + b2 = -37.75

Factor a perfect square on the left side:
(b + -1.5)(b + -1.5) = -37.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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