b(b-6)=27

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Solution for b(b-6)=27 equation:


Simplifying
b(b + -6) = 27

Reorder the terms:
b(-6 + b) = 27
(-6 * b + b * b) = 27
(-6b + b2) = 27

Solving
-6b + b2 = 27

Solving for variable 'b'.

Reorder the terms:
-27 + -6b + b2 = 27 + -27

Combine like terms: 27 + -27 = 0
-27 + -6b + b2 = 0

Factor a trinomial.
(-3 + -1b)(9 + -1b) = 0

Subproblem 1

Set the factor '(-3 + -1b)' equal to zero and attempt to solve: Simplifying -3 + -1b = 0 Solving -3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1b = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1b = 0 + 3 -1b = 0 + 3 Combine like terms: 0 + 3 = 3 -1b = 3 Divide each side by '-1'. b = -3 Simplifying b = -3

Subproblem 2

Set the factor '(9 + -1b)' equal to zero and attempt to solve: Simplifying 9 + -1b = 0 Solving 9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -1b = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -1b = 0 + -9 -1b = 0 + -9 Combine like terms: 0 + -9 = -9 -1b = -9 Divide each side by '-1'. b = 9 Simplifying b = 9

Solution

b = {-3, 9}

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