b(x+c)=a(x-c)+2bc

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Solution for b(x+c)=a(x-c)+2bc equation:


Simplifying
b(x + c) = a(x + -1c) + 2bc

Reorder the terms:
b(c + x) = a(x + -1c) + 2bc
(c * b + x * b) = a(x + -1c) + 2bc
(bc + bx) = a(x + -1c) + 2bc

Reorder the terms:
bc + bx = a(-1c + x) + 2bc
bc + bx = (-1c * a + x * a) + 2bc
bc + bx = (-1ac + ax) + 2bc

Solving
bc + bx = -1ac + ax + 2bc

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2bc' to each side of the equation.
bc + -2bc + bx = -1ac + ax + 2bc + -2bc

Combine like terms: bc + -2bc = -1bc
-1bc + bx = -1ac + ax + 2bc + -2bc

Combine like terms: 2bc + -2bc = 0
-1bc + bx = -1ac + ax + 0
-1bc + bx = -1ac + ax

Reorder the terms:
ac + -1ax + -1bc + bx = -1ac + ax + ac + -1ax

Reorder the terms:
ac + -1ax + -1bc + bx = -1ac + ac + ax + -1ax

Combine like terms: -1ac + ac = 0
ac + -1ax + -1bc + bx = 0 + ax + -1ax
ac + -1ax + -1bc + bx = ax + -1ax

Combine like terms: ax + -1ax = 0
ac + -1ax + -1bc + bx = 0

The solution to this equation could not be determined.

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