b+(25+b)=(3b)+435

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Solution for b+(25+b)=(3b)+435 equation:



b+(25+b)=(3b)+435
We move all terms to the left:
b+(25+b)-((3b)+435)=0
We add all the numbers together, and all the variables
b+(b+25)-(3b+435)=0
We get rid of parentheses
b+b-3b+25-435=0
We add all the numbers together, and all the variables
-1b-410=0
We move all terms containing b to the left, all other terms to the right
-b=410
b=410/-1
b=-410

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