b+(25+b)=(3b)+435

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Solution for b+(25+b)=(3b)+435 equation: 



b+(25+b)=(3b)+435

We move all terms to the left:

b+(25+b)-((3b)+435)=0

We add all the numbers together, and all the variables

b+(b+25)-(3b+435)=0

We get rid of parentheses

b+b-3b+25-435=0

We add all the numbers together, and all the variables

-1b-410=0

We move all terms containing b to the left, all other terms to the right

-b=410

b=410/-1

b=-410

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