b+(3b+2)+(5b-5)=123

Solution for b+(3b+2)+(5b-5)=123 equation:

Simplifying
b + (3b + 2) + (5b + -5) = 123

Reorder the terms:
b + (2 + 3b) + (5b + -5) = 123

Remove parenthesis around (2 + 3b)
b + 2 + 3b + (5b + -5) = 123

Reorder the terms:
b + 2 + 3b + (-5 + 5b) = 123

Remove parenthesis around (-5 + 5b)
b + 2 + 3b + -5 + 5b = 123

Reorder the terms:
2 + -5 + b + 3b + 5b = 123

Combine like terms: 2 + -5 = -3
-3 + b + 3b + 5b = 123

Combine like terms: b + 3b = 4b
-3 + 4b + 5b = 123

Combine like terms: 4b + 5b = 9b
-3 + 9b = 123

Solving
-3 + 9b = 123

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 9b = 123 + 3

Combine like terms: -3 + 3 = 0
0 + 9b = 123 + 3
9b = 123 + 3

Combine like terms: 123 + 3 = 126
9b = 126

Divide each side by '9'.
b = 14

Simplifying
b = 14