b+(b+4)+(b-6)=28

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Solution for b+(b+4)+(b-6)=28 equation:


Simplifying
b + (b + 4) + (b + -6) = 28

Reorder the terms:
b + (4 + b) + (b + -6) = 28

Remove parenthesis around (4 + b)
b + 4 + b + (b + -6) = 28

Reorder the terms:
b + 4 + b + (-6 + b) = 28

Remove parenthesis around (-6 + b)
b + 4 + b + -6 + b = 28

Reorder the terms:
4 + -6 + b + b + b = 28

Combine like terms: 4 + -6 = -2
-2 + b + b + b = 28

Combine like terms: b + b = 2b
-2 + 2b + b = 28

Combine like terms: 2b + b = 3b
-2 + 3b = 28

Solving
-2 + 3b = 28

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 3b = 28 + 2

Combine like terms: -2 + 2 = 0
0 + 3b = 28 + 2
3b = 28 + 2

Combine like terms: 28 + 2 = 30
3b = 30

Divide each side by '3'.
b = 10

Simplifying
b = 10

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