b+(b+45)=90+(2b-90)+1.5b=540

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Solution for b+(b+45)=90+(2b-90)+1.5b=540 equation: 



b+(b+45)=90+(2b-90)+1.5b=540

We move all terms to the left:

b+(b+45)-(90+(2b-90)+1.5b)=0

We get rid of parentheses

b+b-(90+(2b-90)+1.5b)+45=0



We calculate terms in parentheses: -(90+(2b-90)+1.5b), so:

90+(2b-90)+1.5b

determiningTheFunctionDomain
(2b-90)+1.5b+90

We add all the numbers together, and all the variables

1.5b+(2b-90)+90

We get rid of parentheses

1.5b+2b-90+90

We add all the numbers together, and all the variables

3.5b

Back to the equation:

-(3.5b)



We add all the numbers together, and all the variables

b+b-(+3.5b)+45=0

We add all the numbers together, and all the variables

2b-(+3.5b)+45=0

We get rid of parentheses

2b-3.5b+45=0

We add all the numbers together, and all the variables

-1.5b+45=0

We move all terms containing b to the left, all other terms to the right

-1.5b=-45

b=-45/-1.5

b=+30

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