b+(b+45)=90+(2b-90)+1.5b=540

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Solution for b+(b+45)=90+(2b-90)+1.5b=540 equation:



b+(b+45)=90+(2b-90)+1.5b=540
We move all terms to the left:
b+(b+45)-(90+(2b-90)+1.5b)=0
We get rid of parentheses
b+b-(90+(2b-90)+1.5b)+45=0
We calculate terms in parentheses: -(90+(2b-90)+1.5b), so:
90+(2b-90)+1.5b
determiningTheFunctionDomain (2b-90)+1.5b+90
We add all the numbers together, and all the variables
1.5b+(2b-90)+90
We get rid of parentheses
1.5b+2b-90+90
We add all the numbers together, and all the variables
3.5b
Back to the equation:
-(3.5b)
We add all the numbers together, and all the variables
b+b-(+3.5b)+45=0
We add all the numbers together, and all the variables
2b-(+3.5b)+45=0
We get rid of parentheses
2b-3.5b+45=0
We add all the numbers together, and all the variables
-1.5b+45=0
We move all terms containing b to the left, all other terms to the right
-1.5b=-45
b=-45/-1.5
b=+30

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