b+(b-5)=35

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Solution for b+(b-5)=35 equation: 



b+(b-5)=35

We move all terms to the left:

b+(b-5)-(35)=0

We get rid of parentheses

b+b-5-35=0

We add all the numbers together, and all the variables

2b-40=0

We move all terms containing b to the left, all other terms to the right

2b=40

b=40/2

b=20

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