b+1/3b+2/3=2

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Solution for b+1/3b+2/3=2 equation: 



b+1/3b+2/3=2

We move all terms to the left:

b+1/3b+2/3-(2)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



determiningTheFunctionDomain
b+1/3b-2+2/3=0

We calculate fractions


b-2=0

We move all terms containing b to the left, all other terms to the right

b=2

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