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b+1/5b=
We move all terms to the left:
b+1/5b-()=0
Domain of the equation: 5b!=0We add all the numbers together, and all the variables
b!=0/5
b!=0
b∈R
b+1/5b=0
We multiply all the terms by the denominator
b*5b+1=0
Wy multiply elements
5b^2+1=0
a = 5; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·5·1
Δ = -20
Delta is less than zero, so there is no solution for the equation
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