b+10.8=124/5b=

Solution for b+10.8=124/5b= equation:

b+10.8=124/5b=

We move all terms to the left:

b+10.8-(124/5b)=0


Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

b-(+124/5b)+10.8=0

We get rid of parentheses

b-124/5b+10.8=0

We multiply all the terms by the denominator


b*5b+(10.8)*5b-124=0

We multiply parentheses

b*5b+54b-124=0

Wy multiply elements

5b^2+54b-124=0

a = 5; b = 54; c = -124;
Δ = b2-4ac
Δ = 542-4·5·(-124)
Δ = 5396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5396}=\sqrt{4*1349}=\sqrt{4}*\sqrt{1349}=2\sqrt{1349}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{1349}}{2*5}=\frac{-54-2\sqrt{1349}}{10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{1349}}{2*5}=\frac{-54+2\sqrt{1349}}{10}
$