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b+12/9=3
We move all terms to the left:
b+12/9-(3)=0
determiningTheFunctionDomain b-3+12/9=0
We multiply all the terms by the denominator
b*9+12-3*9=0
We add all the numbers together, and all the variables
b*9-15=0
Wy multiply elements
9b-15=0
We move all terms containing b to the left, all other terms to the right
9b=15
b=15/9
b=1+2/3
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