b+12=3(b-4)+2b

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Solution for b+12=3(b-4)+2b equation:


Simplifying
b + 12 = 3(b + -4) + 2b

Reorder the terms:
12 + b = 3(b + -4) + 2b

Reorder the terms:
12 + b = 3(-4 + b) + 2b
12 + b = (-4 * 3 + b * 3) + 2b
12 + b = (-12 + 3b) + 2b

Combine like terms: 3b + 2b = 5b
12 + b = -12 + 5b

Solving
12 + b = -12 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
12 + b + -5b = -12 + 5b + -5b

Combine like terms: b + -5b = -4b
12 + -4b = -12 + 5b + -5b

Combine like terms: 5b + -5b = 0
12 + -4b = -12 + 0
12 + -4b = -12

Add '-12' to each side of the equation.
12 + -12 + -4b = -12 + -12

Combine like terms: 12 + -12 = 0
0 + -4b = -12 + -12
-4b = -12 + -12

Combine like terms: -12 + -12 = -24
-4b = -24

Divide each side by '-4'.
b = 6

Simplifying
b = 6

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