b+12=6b+53

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Solution for b+12=6b+53 equation: 



b+12=6b+53

We move all terms to the left:

b+12-(6b+53)=0

We get rid of parentheses

b-6b-53+12=0

We add all the numbers together, and all the variables

-5b-41=0

We move all terms containing b to the left, all other terms to the right

-5b=41

b=41/-5

b=-8+1/5

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