b+19/12=2

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Solution for b+19/12=2 equation: 



b+19/12=2

We move all terms to the left:

b+19/12-(2)=0

determiningTheFunctionDomain
b-2+19/12=0

We multiply all the terms by the denominator


b*12+19-2*12=0

We add all the numbers together, and all the variables

b*12-5=0

Wy multiply elements

12b-5=0

We move all terms containing b to the left, all other terms to the right

12b=5

b=5/12

b=5/12

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