b+1=14(3b+2)

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Solution for b+1=14(3b+2) equation: 



b+1=14(3b+2)

We move all terms to the left:

b+1-(14(3b+2))=0



We calculate terms in parentheses: -(14(3b+2)), so:

14(3b+2)

We multiply parentheses

42b+28

Back to the equation:

-(42b+28)



We get rid of parentheses

b-42b-28+1=0

We add all the numbers together, and all the variables

-41b-27=0

We move all terms containing b to the left, all other terms to the right

-41b=27

b=27/-41

b=-27/41

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