b+2(b+5)=2(b-1)+13

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Solution for b+2(b+5)=2(b-1)+13 equation: 


Simplifying
b + 2(b + 5) = 2(b + -1) + 13

Reorder the terms:
b + 2(5 + b) = 2(b + -1) + 13
b + (5 * 2 + b * 2) = 2(b + -1) + 13
b + (10 + 2b) = 2(b + -1) + 13

Reorder the terms:
10 + b + 2b = 2(b + -1) + 13

Combine like terms: b + 2b = 3b
10 + 3b = 2(b + -1) + 13

Reorder the terms:
10 + 3b = 2(-1 + b) + 13
10 + 3b = (-1 * 2 + b * 2) + 13
10 + 3b = (-2 + 2b) + 13

Reorder the terms:
10 + 3b = -2 + 13 + 2b

Combine like terms: -2 + 13 = 11
10 + 3b = 11 + 2b

Solving
10 + 3b = 11 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
10 + 3b + -2b = 11 + 2b + -2b

Combine like terms: 3b + -2b = 1b
10 + 1b = 11 + 2b + -2b

Combine like terms: 2b + -2b = 0
10 + 1b = 11 + 0
10 + 1b = 11

Add '-10' to each side of the equation.
10 + -10 + 1b = 11 + -10

Combine like terms: 10 + -10 = 0
0 + 1b = 11 + -10
1b = 11 + -10

Combine like terms: 11 + -10 = 1
1b = 1

Divide each side by '1'.
b = 1

Simplifying
b = 1

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