b+2(b+5)=4(b-1)+13

Solution for b+2(b+5)=4(b-1)+13 equation:

b+2(b+5)=4(b-1)+13

We move all terms to the left:

b+2(b+5)-(4(b-1)+13)=0

We multiply parentheses

b+2b-(4(b-1)+13)+10=0


We calculate terms in parentheses: -(4(b-1)+13), so:

4(b-1)+13

We multiply parentheses

4b-4+13

We add all the numbers together, and all the variables

4b+9

Back to the equation:

-(4b+9)


We add all the numbers together, and all the variables

3b-(4b+9)+10=0

We get rid of parentheses

3b-4b-9+10=0

We add all the numbers together, and all the variables

-1b+1=0

We move all terms containing b to the left, all other terms to the right

-b=-1

b=-1/-1

b=1