b+2(b-8)=20

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Solution for b+2(b-8)=20 equation:



b+2(b-8)=20
We move all terms to the left:
b+2(b-8)-(20)=0
We multiply parentheses
b+2b-16-20=0
We add all the numbers together, and all the variables
3b-36=0
We move all terms containing b to the left, all other terms to the right
3b=36
b=36/3
b=12

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