b+2/3+(2b-90)+90+(b+45)=180

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Solution for b+2/3+(2b-90)+90+(b+45)=180 equation: 



b+2/3+(2b-90)+90+(b+45)=180

We move all terms to the left:

b+2/3+(2b-90)+90+(b+45)-(180)=0

determiningTheFunctionDomain
b+(2b-90)+(b+45)+90-180+2/3=0

We add all the numbers together, and all the variables

b+(2b-90)+(b+45)-90+2/3=0

We get rid of parentheses

b+2b+b-90+45-90+2/3=0

We multiply all the terms by the denominator


b*3+2b*3+b*3+2-90*3+45*3-90*3=0

We add all the numbers together, and all the variables

b*3+2b*3+b*3-403=0

Wy multiply elements

3b+6b+3b-403=0

We add all the numbers together, and all the variables

12b-403=0

We move all terms containing b to the left, all other terms to the right

12b=403

b=403/12

b=33+7/12

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