b+27=3(1-2b)+3

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Solution for b+27=3(1-2b)+3 equation: 



b+27=3(1-2b)+3

We move all terms to the left:

b+27-(3(1-2b)+3)=0

We add all the numbers together, and all the variables

b-(3(-2b+1)+3)+27=0



We calculate terms in parentheses: -(3(-2b+1)+3), so:

3(-2b+1)+3

We multiply parentheses

-6b+3+3

We add all the numbers together, and all the variables

-6b+6

Back to the equation:

-(-6b+6)



We get rid of parentheses

b+6b-6+27=0

We add all the numbers together, and all the variables

7b+21=0

We move all terms containing b to the left, all other terms to the right

7b=-21

b=-21/7

b=-3

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