b+2b+(2b-12)=128

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Solution for b+2b+(2b-12)=128 equation: 



b+2b+(2b-12)=128

We move all terms to the left:

b+2b+(2b-12)-(128)=0

We add all the numbers together, and all the variables

3b+(2b-12)-128=0

We get rid of parentheses

3b+2b-12-128=0

We add all the numbers together, and all the variables

5b-140=0

We move all terms containing b to the left, all other terms to the right

5b=140

b=140/5

b=28

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