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b+2b-10=10(b+5)+15+b=
We move all terms to the left:
b+2b-10-(10(b+5)+15+b)=0
We add all the numbers together, and all the variables
3b-(10(b+5)+15+b)-10=0
We calculate terms in parentheses: -(10(b+5)+15+b), so:We get rid of parentheses
10(b+5)+15+b
determiningTheFunctionDomain 10(b+5)+b+15
We add all the numbers together, and all the variables
b+10(b+5)+15
We multiply parentheses
b+10b+50+15
We add all the numbers together, and all the variables
11b+65
Back to the equation:
-(11b+65)
3b-11b-65-10=0
We add all the numbers together, and all the variables
-8b-75=0
We move all terms containing b to the left, all other terms to the right
-8b=75
b=75/-8
b=-9+3/8
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