b+2b-10=10*(b+5)+15+b

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Solution for b+2b-10=10*(b+5)+15+b equation: 



b+2b-10=10(b+5)+15+b

We move all terms to the left:

b+2b-10-(10(b+5)+15+b)=0

We add all the numbers together, and all the variables

3b-(10(b+5)+15+b)-10=0



We calculate terms in parentheses: -(10(b+5)+15+b), so:

10(b+5)+15+b

determiningTheFunctionDomain
10(b+5)+b+15

We add all the numbers together, and all the variables

b+10(b+5)+15

We multiply parentheses

b+10b+50+15

We add all the numbers together, and all the variables

11b+65

Back to the equation:

-(11b+65)



We get rid of parentheses

3b-11b-65-10=0

We add all the numbers together, and all the variables

-8b-75=0

We move all terms containing b to the left, all other terms to the right

-8b=75

b=75/-8

b=-9+3/8

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