b+2b-10=10b+50+15b

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Solution for b+2b-10=10b+50+15b equation: 



b+2b-10=10b+50+15b

We move all terms to the left:

b+2b-10-(10b+50+15b)=0

We add all the numbers together, and all the variables

b+2b-(25b+50)-10=0

We add all the numbers together, and all the variables

3b-(25b+50)-10=0

We get rid of parentheses

3b-25b-50-10=0

We add all the numbers together, and all the variables

-22b-60=0

We move all terms containing b to the left, all other terms to the right

-22b=60

b=60/-22

b=-2+8/11

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