b+3-4b=3-3(b+4)

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Solution for b+3-4b=3-3(b+4) equation: 



b+3-4b=3-3(b+4)

We move all terms to the left:

b+3-4b-(3-3(b+4))=0

We add all the numbers together, and all the variables

-3b-(3-3(b+4))+3=0



We calculate terms in parentheses: -(3-3(b+4)), so:

3-3(b+4)

determiningTheFunctionDomain
-3(b+4)+3

We multiply parentheses

-3b-12+3

We add all the numbers together, and all the variables

-3b-9

Back to the equation:

-(-3b-9)



We get rid of parentheses

-3b+3b+9+3=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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