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b+3-4b=3-3(b+4)
We move all terms to the left:
b+3-4b-(3-3(b+4))=0
We add all the numbers together, and all the variables
-3b-(3-3(b+4))+3=0
We calculate terms in parentheses: -(3-3(b+4)), so:We get rid of parentheses
3-3(b+4)
determiningTheFunctionDomain -3(b+4)+3
We multiply parentheses
-3b-12+3
We add all the numbers together, and all the variables
-3b-9
Back to the equation:
-(-3b-9)
-3b+3b+9+3=0
We add all the numbers together, and all the variables
12!=0
There is no solution for this equation
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