b+3/2b(b+45)(-2b-90)+90=540

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Solution for b+3/2b(b+45)(-2b-90)+90=540 equation: 



b+3/2b(b+45)(-2b-90)+90=540

We move all terms to the left:

b+3/2b(b+45)(-2b-90)+90-(540)=0



Domain of the equation: 2b(b+45)(-2b-90)!=0

b∈R



We add all the numbers together, and all the variables

b+3/2b(b+45)(-2b-90)-450=0

We multiply parentheses ..

3/2b(-2b^2-90b-90b-4050)+b-450=0

We multiply all the terms by the denominator


b*2b(-2b^2-90b-90b-4050)-450*2b(-2b^2-90b-90b-4050)+3=0

Wy multiply elements

2b^2(--900b(-+3=0

We use the square of the difference formula

2b^2(+900b(-3=0

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