b+3/2b(b+45)+(2b-90)+90=450

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Solution for b+3/2b(b+45)+(2b-90)+90=450 equation: 



b+3/2b(b+45)+(2b-90)+90=450

We move all terms to the left:

b+3/2b(b+45)+(2b-90)+90-(450)=0



Domain of the equation: 2b(b+45)!=0

b∈R



We add all the numbers together, and all the variables

b+3/2b(b+45)+(2b-90)-360=0

We get rid of parentheses

b+3/2b(b+45)+2b-90-360=0

We multiply all the terms by the denominator


b*2b(b+45)+2b*2b(b+45)-90*2b(b+45)-360*2b(b+45)+3=0

Wy multiply elements

2b^2(b+4b^2(b-180b(b-720b(b+3=0

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