b+3/2b+(b+45)(2b-90)+90=540

Solution for b+3/2b+(b+45)(2b-90)+90=540 equation:

b+3/2b+(b+45)(2b-90)+90=540

We move all terms to the left:

b+3/2b+(b+45)(2b-90)+90-(540)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

b+3/2b+(b+45)(2b-90)-450=0

We multiply parentheses ..

(+2b^2-90b+90b-4050)+b+3/2b-450=0

We multiply all the terms by the denominator


((+2b^2-90b+90b-4050))*2b+b*2b-450*2b+3=0

Wy multiply elements

((+2b^2-90b+90b-4050))*2b+2b^2-900b+3=0

We add all the numbers together, and all the variables

2b^2+((+2b^2-90b+90b-4050))*2b-900b+3=0

We move all terms containing b to the left, all other terms to the right

2b^2+((+2b^2-90b+90b-4050))*2b-900b=-3