b+3/2b+(b=45)+(2b-90)+90=540

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Solution for b+3/2b+(b=45)+(2b-90)+90=540 equation: 



b+3/2b+(b=45)+(2b-90)+90=540

We move all terms to the left:

b+3/2b+(b-(45)+(2b-90)+90)=0



Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R



We multiply all the terms by the denominator


b*2b+((b-45+(2b-90)+90))*2b+3=0

Wy multiply elements

2b^2+((b-45+(2b-90)+90))*2b+3=0

We move all terms containing b to the left, all other terms to the right

2b^2+((b-45+(2b-90)+90))*2b=-3

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