b+3/2b+b+45+26-90+90=540

Solution for b+3/2b+b+45+26-90+90=540 equation:

b+3/2b+b+45+26-90+90=540

We move all terms to the left:

b+3/2b+b+45+26-90+90-(540)=0


Domain of the equation: 2b!=0

b!=0/2

b!=0

b∈R


We add all the numbers together, and all the variables

2b+3/2b-469=0

We multiply all the terms by the denominator


2b*2b-469*2b+3=0

Wy multiply elements

4b^2-938b+3=0

a = 4; b = -938; c = +3;
Δ = b2-4ac
Δ = -9382-4·4·3
Δ = 879796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{879796}=\sqrt{4*219949}=\sqrt{4}*\sqrt{219949}=2\sqrt{219949}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-938)-2\sqrt{219949}}{2*4}=\frac{938-2\sqrt{219949}}{8}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-938)+2\sqrt{219949}}{2*4}=\frac{938+2\sqrt{219949}}{8}
$