b+3/5=7

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Solution for b+3/5=7 equation: 



b+3/5=7

We move all terms to the left:

b+3/5-(7)=0

determiningTheFunctionDomain
b-7+3/5=0

We multiply all the terms by the denominator


b*5+3-7*5=0

We add all the numbers together, and all the variables

b*5-32=0

Wy multiply elements

5b-32=0

We move all terms containing b to the left, all other terms to the right

5b=32

b=32/5

b=6+2/5

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