b+3=1/2(b-4)

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Solution for b+3=1/2(b-4) equation: 



b+3=1/2(b-4)

We move all terms to the left:

b+3-(1/2(b-4))=0



Domain of the equation: 2(b-4))!=0

b∈R



We multiply all the terms by the denominator


b*2(b-4))-(1+3*2(b-4))=0

Wy multiply elements

2b^2(b+6b(b=0

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