b+3b+12=96

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Solution for b+3b+12=96 equation: 



b+3b+12=96

We move all terms to the left:

b+3b+12-(96)=0

We add all the numbers together, and all the variables

4b-84=0

We move all terms containing b to the left, all other terms to the right

4b=84

b=84/4

b=21

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