b+3b+2+5b-5=123

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Solution for b+3b+2+5b-5=123 equation: 



b+3b+2+5b-5=123

We move all terms to the left:

b+3b+2+5b-5-(123)=0

We add all the numbers together, and all the variables

9b-126=0

We move all terms containing b to the left, all other terms to the right

9b=126

b=126/9

b=14

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