b+3b-12=48

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Solution for b+3b-12=48 equation: 



b+3b-12=48

We move all terms to the left:

b+3b-12-(48)=0

We add all the numbers together, and all the variables

4b-60=0

We move all terms containing b to the left, all other terms to the right

4b=60

b=60/4

b=15

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