b+40/3=2

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Solution for b+40/3=2 equation: 



b+40/3=2

We move all terms to the left:

b+40/3-(2)=0

determiningTheFunctionDomain
b-2+40/3=0

We multiply all the terms by the denominator


b*3+40-2*3=0

We add all the numbers together, and all the variables

b*3+34=0

Wy multiply elements

3b+34=0

We move all terms containing b to the left, all other terms to the right

3b=-34

b=-34/3

b=-11+1/3

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